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Problem of the day 17.07.09

with 10 comments

Find the area of right angle triangle whose inradius is 4 and circumradius
is 10?
a) 28                   b) 56                    c) 96                     d) 192                   e) none of these


Written by Implex

July 16, 2009 at 2:35 pm

10 Responses

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  1. 96 🙂


    July 16, 2009 at 3:31 pm

  2. Nice, yet again!


    July 16, 2009 at 3:50 pm

  3. Is the length of the altitutude (drawn to the hypotenuse) = 1/2(length of hypot.?)
    if so..the hyp=28..is that correct??


    July 17, 2009 at 9:23 am

  4. no boss
    its 20 hyp


    July 20, 2009 at 1:02 pm

  5. ans is 96
    rahul sir i met you once in CL,you gave lecture on better preparation in gagan sir’s class.
    you are doing great job..i owe much to your lessons/concepts
    thank you


    July 24, 2009 at 8:22 am

  6. Shivam

    I am sure you are mistaking me for someone else.
    I am not aware of any gagan sir and have never been to a Cl class


    July 24, 2009 at 8:59 pm

  7. how to solve this problem


    July 25, 2009 at 2:43 pm

  8. the smallest right triangle is 345
    with inradius 1 and circumradius 2.5
    what we need is a triangle which has four times the given values
    hence the area will be 16 times that of the given triangle
    hnce 16×6=96


    July 25, 2009 at 2:46 pm

  9. thank’s Rahul


    July 26, 2009 at 11:44 am

  10. 4(r+2R)=Area


    July 10, 2017 at 9:18 am

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