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Problem of the day 17.07.09

with 9 comments


Find the area of right angle triangle whose inradius is 4 and circumradius
is 10?
a) 28                   b) 56                    c) 96                     d) 192                   e) none of these

Written by Implex

July 16, 2009 at 2:35 pm

9 Responses

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  1. 96🙂

    Nikhil

    July 16, 2009 at 3:31 pm

  2. Nice, yet again!

    Rahul

    July 16, 2009 at 3:50 pm

  3. Is the length of the altitutude (drawn to the hypotenuse) = 1/2(length of hypot.?)
    if so..the hyp=28..is that correct??

    Sam

    July 17, 2009 at 9:23 am

  4. no boss
    its 20 hyp

    kuldeep

    July 20, 2009 at 1:02 pm

  5. ans is 96
    rahul sir i met you once in CL,you gave lecture on better preparation in gagan sir’s class.
    you are doing great job..i owe much to your lessons/concepts
    thank you
    shivam

    shivam

    July 24, 2009 at 8:22 am

  6. Shivam

    I am sure you are mistaking me for someone else.
    I am not aware of any gagan sir and have never been to a Cl class

    Rahul

    July 24, 2009 at 8:59 pm

  7. how to solve this problem

    rahul

    July 25, 2009 at 2:43 pm

  8. the smallest right triangle is 345
    with inradius 1 and circumradius 2.5
    what we need is a triangle which has four times the given values
    hence the area will be 16 times that of the given triangle
    hnce 16×6=96

    Rahul

    July 25, 2009 at 2:46 pm

  9. thank’s Rahul

    rahul

    July 26, 2009 at 11:44 am


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