i would like to clearify that its the fermat rule that
x^n + y^n = z^n…n>=3 has no sloution…else we can solve it by jst hit n trial and reach the solution

Fermat’s last theorem states that there is no NON trivial solution for the equation written above for n > 2. (0,0,0) is always a solution to such equation for all n>0.

intuitively, the fourth powers are 1,16,81,256,… etc.. for bigger numbers the gap between these fourth powers is too huge to be compensated by a smaller fourth power. so this equation can only be fulfilled among the smaller fourth powers. however as is evident from these numbers, no such combination is possible. so 0

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choice A) 0 ??

SamJuly 17, 2009 at 9:34 am

rahul,can u tell the solution of this question

PrateekJuly 17, 2009 at 9:48 am

it’s the fermat’s last theorem.And no one till date has been able to prove this.

x^n + y^n = z^n for n>2 (does not hold).

yodhaJuly 17, 2009 at 3:13 pm

answer : 0

yodha’ sol sounds correct .

but in case a person isnot aware of fermat’s last theorem then what ??

nikhilJuly 18, 2009 at 6:52 am

the solution is right..

we do not have a perfect solution for this question.

but intutively we can solve this

RahulJuly 23, 2009 at 6:46 am

clearly 0 is a solution

ANKIT PANGHALAugust 10, 2009 at 10:04 am

i would like to clearify that its the fermat rule that

x^n + y^n = z^n…n>=3 has no sloution…else we can solve it by jst hit n trial and reach the solution

ANKIT PANGHALAugust 13, 2009 at 4:27 am

Fermat’s last theorem states that there is no NON trivial solution for the equation written above for n > 2. (0,0,0) is always a solution to such equation for all n>0.

KshitizOctober 11, 2009 at 11:36 am

In Fermat’s last theorem n is integer. And it has been proven in 1993 by Andrew Wiles and Richard Taylor.

KshitizOctober 11, 2009 at 11:37 am

intuitively, the fourth powers are 1,16,81,256,… etc.. for bigger numbers the gap between these fourth powers is too huge to be compensated by a smaller fourth power. so this equation can only be fulfilled among the smaller fourth powers. however as is evident from these numbers, no such combination is possible. so 0

PranshuNovember 10, 2009 at 2:46 pm