## Bonus Question 16.07.09

**Find the number of solutions in distinct positive integers of x^4+y^4=z^4**

**A) 0 B) 1 C) 2 D) 3 E) More than 3**

Advertisements

For All Your Quant Queries

**Find the number of solutions in distinct positive integers of x^4+y^4=z^4**

**A) 0 B) 1 C) 2 D) 3 E) More than 3**

Advertisements

Written by Implex

July 16, 2009 at 3:27 pm

Posted in Algebra, CAT 2009, Number Thoery, Online CAT, Problem of the week, Problems

Tagged with Algebra, cat, CAT 2009, IIM, Mock Cat, Mock Quant, Number Theory, Online CAT

Subscribe to comments with RSS.

- Para Jumbles 19.08.09
- Fill In the blanks 08.08.09
- Fill In The Blanks 05.08.09
- Para Jumbles 05.08.09
- Para Jumbles 04.08.09

- Algebra
- Announcements
- Arithmetic
- CAT 2008
- CAT 2009
- Combinatorics
- concepts
- Conundrum
- Coordinate Geometry
- Data Sufficiency
- Functions
- General
- Geometry
- IIM Interview Experiences
- Inequalities
- Mock Cat
- Mock Quant
- Number Thoery
- Online CAT
- Power Play
- Prime Numbers
- Probability
- Problem of the week
- Problems
- Tips

- Problem of the day 26.08.09
- Problem of The day 06.08.09
- Problem of the Day 30.07.09
- Bonus QUestion 28.07.09
- Problem of the day 28.07.09

- Art of Problem Solving
- CAT Material (free)
- Math Lessons
- Pagal Guy
- Pagalbille
- Test Funda
- Verbal Logic

- Concept 1 Perfect Squares
- Concept 5 Pigeon- Hole Principle
- Problem of the day 27.07.09
- CAT 2008 Key and Solutions
- Problems 8.07.09

sujeet3035 on Problem of the day 17.07.… | |

vinit on Bonus Question 26.07.09 | |

harsh bansal on The Funny Side of Mathema… | |

KT on IIM A Interview Experienc… | |

tushar on Concept 3 Circle and Triangles… |

- 126,221 hits

- RT @dd85518: @free_thinker @padhalikha Go for it sir. Tell the world that your father never cheated on your mom for Rana bibi. Expose your… 1 hour ago
- RT @MukulAgarwal66: cc @myogiadityanath Please take action twitter.com/ShivAroor/stat… 2 hours ago
- RT @coolfunnytshirt: This is the end product you get when you turn on the mixer to mix a comedian with a political analyst and a twitter ac… 2 hours ago
- RT @bhak_sala: Not long back, Swati Chaturvedi revealed my personal details on twitter and organized mass attacks on me. Now Pratik is reve… 4 hours ago
- RT @AFixedPoint_: Scary stuff. The opposition is now openly talking about Narendra Modi’s assassination. Hope Modi does not do any more roa… 4 hours ago

%d bloggers like this:

choice A) 0 ??

SamJuly 17, 2009 at 9:34 am

rahul,can u tell the solution of this question

PrateekJuly 17, 2009 at 9:48 am

it’s the fermat’s last theorem.And no one till date has been able to prove this.

x^n + y^n = z^n for n>2 (does not hold).

yodhaJuly 17, 2009 at 3:13 pm

answer : 0

yodha’ sol sounds correct .

but in case a person isnot aware of fermat’s last theorem then what ??

nikhilJuly 18, 2009 at 6:52 am

the solution is right..

we do not have a perfect solution for this question.

but intutively we can solve this

RahulJuly 23, 2009 at 6:46 am

clearly 0 is a solution

ANKIT PANGHALAugust 10, 2009 at 10:04 am

i would like to clearify that its the fermat rule that

x^n + y^n = z^n…n>=3 has no sloution…else we can solve it by jst hit n trial and reach the solution

ANKIT PANGHALAugust 13, 2009 at 4:27 am

Fermat’s last theorem states that there is no NON trivial solution for the equation written above for n > 2. (0,0,0) is always a solution to such equation for all n>0.

KshitizOctober 11, 2009 at 11:36 am

In Fermat’s last theorem n is integer. And it has been proven in 1993 by Andrew Wiles and Richard Taylor.

KshitizOctober 11, 2009 at 11:37 am

intuitively, the fourth powers are 1,16,81,256,… etc.. for bigger numbers the gap between these fourth powers is too huge to be compensated by a smaller fourth power. so this equation can only be fulfilled among the smaller fourth powers. however as is evident from these numbers, no such combination is possible. so 0

PranshuNovember 10, 2009 at 2:46 pm