## Problem of The day 13.07.09

On a circle 26 equidistant points are marked. these points are joined to form a triangles. Of the triangles formed, how many of them will have their circumcenter on one of their sides.?

**A) 318 B) 312 C) 288 d) 624 e) None of these**

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Is answer 288?

SumitJuly 13, 2009 at 5:28 pm

No Sumit!

RahulJuly 13, 2009 at 6:08 pm

according to given condn…d triangles shld be “rightangled” so……right angle is only formed when one f d side is a diameter..den in such case..

option(a) might be the answer..318

anupJuly 14, 2009 at 6:30 am

@Anup, your reasoning is right, you have made a calculation error.

RahulJuly 14, 2009 at 7:36 am

13*24

anonymousJuly 14, 2009 at 6:16 pm

the triangle must be right triangle and hence two points chosen must form the diameter.

13 diametrically opposite points can be chosen and for each of these points we have 24 other points remaining,hence it shud be 24×13=312

abhishekJuly 17, 2009 at 7:48 am

If the points are equidistant then how can they form right angled triangle, why cant they form equilateral triangle

rajuApril 19, 2010 at 5:45 pm

26*24 = 624

am i right dude?

RAJUMay 26, 2010 at 11:48 am