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Problem of The day 13.07.09

with 8 comments


On a circle 26 equidistant points are marked. these points are joined to form a triangles. Of the triangles formed, how many of them will have their circumcenter on one of their sides.?

A) 318 B) 312 C) 288 d) 624 e) None of these

Written by Implex

July 13, 2009 at 2:00 pm

8 Responses

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  1. Is answer 288?

    Sumit

    July 13, 2009 at 5:28 pm

  2. No Sumit!

    Rahul

    July 13, 2009 at 6:08 pm

  3. according to given condn…d triangles shld be “rightangled” so……right angle is only formed when one f d side is a diameter..den in such case..
    option(a) might be the answer..318

    anup

    July 14, 2009 at 6:30 am

  4. @Anup, your reasoning is right, you have made a calculation error.

    Rahul

    July 14, 2009 at 7:36 am

  5. 13*24

    anonymous

    July 14, 2009 at 6:16 pm

  6. the triangle must be right triangle and hence two points chosen must form the diameter.
    13 diametrically opposite points can be chosen and for each of these points we have 24 other points remaining,hence it shud be 24×13=312

    abhishek

    July 17, 2009 at 7:48 am

  7. If the points are equidistant then how can they form right angled triangle, why cant they form equilateral triangle

    raju

    April 19, 2010 at 5:45 pm

  8. 26*24 = 624

    am i right dude?

    RAJU

    May 26, 2010 at 11:48 am


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