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On a circle 26 equidistant points are marked. these points are joined to form a triangles. Of the triangles formed, how many of them will have their circumcenter on one of their sides.?
A) 318 B) 312 C) 288 d) 624 e) None of these
Written by Implex
July 13, 2009 at 2:00 pm
Posted in Algebra, CAT 2009, Combinatorics, Geometry, Mock Cat, Mock Quant, Online CAT, Problem of the week, Problems
Tagged with Algebra, CAT 2009, Combinatorics, Geometry, IIM, Online CAT
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Is answer 288?
July 13, 2009 at 5:28 pm
July 13, 2009 at 6:08 pm
according to given condn…d triangles shld be “rightangled” so……right angle is only formed when one f d side is a diameter..den in such case..
option(a) might be the answer..318
July 14, 2009 at 6:30 am
@Anup, your reasoning is right, you have made a calculation error.
July 14, 2009 at 7:36 am
July 14, 2009 at 6:16 pm
the triangle must be right triangle and hence two points chosen must form the diameter.
13 diametrically opposite points can be chosen and for each of these points we have 24 other points remaining,hence it shud be 24×13=312
July 17, 2009 at 7:48 am
If the points are equidistant then how can they form right angled triangle, why cant they form equilateral triangle
April 19, 2010 at 5:45 pm
26*24 = 624
am i right dude?
May 26, 2010 at 11:48 am
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