Two triangles are considered distinct if they cannot be superimposed on each other by rotation. How many distinct triangles, with integer sides, exist, such that there perimeter is 30?

suppose d given triangles are equilateral..den dere side=20..so 18 distinct triangles can be formed…den findout d area of circum circle..proceeding in dat way i found its near 60…m not sure..but help me out

is the answer a) 19 ?
i.e. how i approached this question
since all(any two) the sides are less than half the perimeter.
14 ,14 ,2
14 ,13 ,3
14 ,12 ,4
. .
8 8 = total 7 possibilities.
similary
13 ,13 ,4
13 ,12 ,5
13 ,11 ,6
likewise we can do for 12 , 11 and 10.
giving a total of 19.

is the answer a) 19 ?
i.e. how i approached this question
since all(any two) the sides are less than half the perimeter.
14 ,14 ,2
14 ,13 ,3
14 ,12 ,4
. .
8 8 = total 7 possibilities.
similary
13 ,13 ,4
13 ,12 ,5
13 ,11 ,6
likewise we can do for 12 , 11 and 10.
giving a total of 19.

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option B????

anupJuly 2, 2009 at 7:16 am

Kindly post your process, i will know if it is right or not!

RahulJuly 2, 2009 at 7:29 am

suppose d given triangles are equilateral..den dere side=20..so 18 distinct triangles can be formed…den findout d area of circum circle..proceeding in dat way i found its near 60…m not sure..but help me out

anupJuly 2, 2009 at 7:43 am

You need to think in terms of triangle inequalities

RahulJuly 2, 2009 at 7:44 am

is the answer a) 19 ?

i.e. how i approached this question

since all(any two) the sides are less than half the perimeter.

14 ,14 ,2

14 ,13 ,3

14 ,12 ,4

. .

8 8 = total 7 possibilities.

similary

13 ,13 ,4

13 ,12 ,5

13 ,11 ,6

likewise we can do for 12 , 11 and 10.

giving a total of 19.

correct me if i m wrong.

yodhaJuly 4, 2009 at 3:32 pm

One sincere question..

Could we have a facility of subscribing to the posts of this blog. This blog is a boon to CAT aspirants.🙂

And could you provide solutions at the end of 48 hours or a specific period?

If it’s not asking too much🙂

AnishJuly 4, 2009 at 8:03 pm

https://quantologic.wordpress.com/feed/

there is a feed button out there!🙂

Yeah I generally provide solutions.

I was away traveling and little busy tonight. I hope to satisfy all your needs by tomorrow or day after.

Good Luck

RahulJuly 6, 2009 at 3:37 pm

is the answer a) 19 ?

i.e. how i approached this question

since all(any two) the sides are less than half the perimeter.

14 ,14 ,2

14 ,13 ,3

14 ,12 ,4

. .

8 8 = total 7 possibilities.

similary

13 ,13 ,4

13 ,12 ,5

13 ,11 ,6

likewise we can do for 12 , 11 and 10.

giving a total of 19.

correct me if i m wrong

yodhaJuly 16, 2009 at 5:12 am

what is the answer to this question ????

yodhaJuly 16, 2009 at 5:16 am

it’s 19 i guess

RahulJuly 16, 2009 at 5:18 am