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Problem Of The Week 50

with 4 comments


Find the number of unordered triplets (x,y,z) of positive integers such that x³+y³+z³=2008

1) 0

2) 1

3) 2

4) 3

5) None of these

Written by Implex

October 9, 2008 at 4:05 pm

4 Responses

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  1. is the answer 1 (4,6,12)????

    ankaj

    October 9, 2008 at 7:06 pm

  2. no

    outtimed

    October 9, 2008 at 7:12 pm

  3. 2 pairs (12,6,4)(10,10,2)

    Celebrating Life

    October 13, 2008 at 9:01 am

  4. any general way to solve it…??
    or u just reached the conclusion by making an analogous C program or by hit and trial??

    wolverine

    October 29, 2008 at 12:54 pm


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