## Problem Of The Week 44

**FInd the number of pairs (x,y) of integers 0<x<y such that sqrt(x)+sqrt(y)=sqrt(1984)**

Advertisements

For All Your Quant Queries

**FInd the number of pairs (x,y) of integers 0<x<y such that sqrt(x)+sqrt(y)=sqrt(1984)**

Advertisements

Written by Implex

October 5, 2008 at 10:52 am

Posted in Number Thoery, Problem of the week

Tagged with Number Theory, Problem of the week

Subscribe to comments with RSS.

- Para Jumbles 19.08.09
- Fill In the blanks 08.08.09
- Fill In The Blanks 05.08.09
- Para Jumbles 05.08.09
- Para Jumbles 04.08.09

- Algebra
- Announcements
- Arithmetic
- CAT 2008
- CAT 2009
- Combinatorics
- concepts
- Conundrum
- Coordinate Geometry
- Data Sufficiency
- Functions
- General
- Geometry
- IIM Interview Experiences
- Inequalities
- Mock Cat
- Mock Quant
- Number Thoery
- Online CAT
- Power Play
- Prime Numbers
- Probability
- Problem of the week
- Problems
- Tips

- Problem of the day 26.08.09
- Problem of The day 06.08.09
- Problem of the Day 30.07.09
- Bonus QUestion 28.07.09
- Problem of the day 28.07.09

- Art of Problem Solving
- CAT Material (free)
- Math Lessons
- Pagal Guy
- Pagalbille
- Test Funda
- Verbal Logic

- Concept 1 Perfect Squares
- Concept 5 Pigeon- Hole Principle
- Problem of the day 27.07.09
- CAT 2008 Key and Solutions
- Problems 8.07.09

sujeet3035 on Problem of the day 17.07.… | |

vinit on Bonus Question 26.07.09 | |

harsh bansal on The Funny Side of Mathema… | |

KT on IIM A Interview Experienc… | |

tushar on Concept 3 Circle and Triangles… |

- 126,221 hits

- RT @dd85518: @free_thinker @padhalikha Go for it sir. Tell the world that your father never cheated on your mom for Rana bibi. Expose your… 2 hours ago
- RT @MukulAgarwal66: cc @myogiadityanath Please take action twitter.com/ShivAroor/stat… 2 hours ago
- RT @coolfunnytshirt: This is the end product you get when you turn on the mixer to mix a comedian with a political analyst and a twitter ac… 2 hours ago
- RT @bhak_sala: Not long back, Swati Chaturvedi revealed my personal details on twitter and organized mass attacks on me. Now Pratik is reve… 4 hours ago
- RT @AFixedPoint_: Scary stuff. The opposition is now openly talking about Narendra Modi’s assassination. Hope Modi does not do any more roa… 4 hours ago

%d bloggers like this:

991 pairs

1,(1983)^2 to (991)^2,(993)^2

tyroOctober 5, 2008 at 12:02 pm

pairs can be [1,1983], [2,1982]…..[1984,1]. {for sqrt {x} and sqrt{y}}

but y>x, so, sqrt{y}>sqrt{x}. so, pairs are till before{991,991}

hence, there are 990 pairs for root{y} and root{x} . and there fore for x and y too.

qwertyOctober 5, 2008 at 2:28 pm

sorry there was an error in question

kindly try again !

outtimedOctober 5, 2008 at 4:19 pm

Is the answer 3?

AmitOctober 5, 2008 at 5:16 pm

yeah !! it is 3

outtimedOctober 5, 2008 at 5:26 pm

(1,7) (2,6) (3,5)

each number in each pair multiplied by sqrt(31)

tyroOctober 6, 2008 at 11:49 am

yaar, we have to give (x,y) pairs. so there are 6 pairs.

3 others are (7,1) ,(6,2) , (5,3). correct me if i am wrong.

yodhaOctober 20, 2008 at 3:36 pm

no the answer would still be three because x must be less than y

ALDecember 17, 2008 at 1:15 am