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	<title>Comments for Ultimate Quant Marathon Blog For IIM CAT</title>
	<atom:link href="http://quantologic.wordpress.com/comments/feed/" rel="self" type="application/rss+xml" />
	<link>http://quantologic.wordpress.com</link>
	<description>For All Your Quant Queries</description>
	<lastBuildDate>Thu, 22 Oct 2009 13:02:57 +0000</lastBuildDate>
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		<title>Comment on Problem of the day 28.07.09 by shashank</title>
		<link>http://quantologic.wordpress.com/2009/07/27/problem-of-the-day-28-07-09/#comment-794</link>
		<dc:creator>shashank</dc:creator>
		<pubDate>Thu, 22 Oct 2009 13:02:57 +0000</pubDate>
		<guid isPermaLink="false">http://quantologic.wordpress.com/?p=425#comment-794</guid>
		<description>is the answer for the area problem of the right angled traiangle whose perimeter is 60 and lenth from hypotenuse is 12 is 150?</description>
		<content:encoded><![CDATA[<p>is the answer for the area problem of the right angled traiangle whose perimeter is 60 and lenth from hypotenuse is 12 is 150?</p>
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	</item>
	<item>
		<title>Comment on Concept 1 Perfect Squares by Avinash</title>
		<link>http://quantologic.wordpress.com/2008/08/25/concept-i-perfect-squares/#comment-793</link>
		<dc:creator>Avinash</dc:creator>
		<pubDate>Wed, 21 Oct 2009 14:01:38 +0000</pubDate>
		<guid isPermaLink="false">http://quantologic.wordpress.com/?p=5#comment-793</guid>
		<description>Hi, 

I just found your blog and I feel that its among the most useful sources of information for CAT aspirants. 
Your lucid explanations of CAT quant concepts are extremely helpful and something that every aspirant can use.

I really appreciate the effort that you have put in for MBA aspirants in India! 

I am an online education enthusiast myself and I am looking to collaborate with you to aid Indian students. Please contact me, so that we can explore common synergies. You can reach me at: avinash[dot]chandra[at]savvica.com

Best regards,
Avinash</description>
		<content:encoded><![CDATA[<p>Hi, </p>
<p>I just found your blog and I feel that its among the most useful sources of information for CAT aspirants.<br />
Your lucid explanations of CAT quant concepts are extremely helpful and something that every aspirant can use.</p>
<p>I really appreciate the effort that you have put in for MBA aspirants in India! </p>
<p>I am an online education enthusiast myself and I am looking to collaborate with you to aid Indian students. Please contact me, so that we can explore common synergies. You can reach me at: avinash[dot]chandra[at]savvica.com</p>
<p>Best regards,<br />
Avinash</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Bonus Question 16.07.09 by Kshitiz</title>
		<link>http://quantologic.wordpress.com/2009/07/16/bonus-question-16-07-09/#comment-792</link>
		<dc:creator>Kshitiz</dc:creator>
		<pubDate>Sun, 11 Oct 2009 11:37:51 +0000</pubDate>
		<guid isPermaLink="false">http://quantologic.wordpress.com/?p=412#comment-792</guid>
		<description>In Fermat&#039;s last theorem n is integer. And it has been proven in 1993 by Andrew Wiles and Richard Taylor.</description>
		<content:encoded><![CDATA[<p>In Fermat&#8217;s last theorem n is integer. And it has been proven in 1993 by Andrew Wiles and Richard Taylor.</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Bonus Question 16.07.09 by Kshitiz</title>
		<link>http://quantologic.wordpress.com/2009/07/16/bonus-question-16-07-09/#comment-791</link>
		<dc:creator>Kshitiz</dc:creator>
		<pubDate>Sun, 11 Oct 2009 11:36:05 +0000</pubDate>
		<guid isPermaLink="false">http://quantologic.wordpress.com/?p=412#comment-791</guid>
		<description>Fermat&#039;s last theorem states that there is no NON trivial solution for the equation written above for n &gt; 2. (0,0,0) is always a solution to such equation for all n&gt;0.</description>
		<content:encoded><![CDATA[<p>Fermat&#8217;s last theorem states that there is no NON trivial solution for the equation written above for n &gt; 2. (0,0,0) is always a solution to such equation for all n&gt;0.</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on The Funny Side of Mathematics by deepak sharma</title>
		<link>http://quantologic.wordpress.com/2009/04/03/the-funny-side-of-mathematics/#comment-790</link>
		<dc:creator>deepak sharma</dc:creator>
		<pubDate>Fri, 25 Sep 2009 12:06:52 +0000</pubDate>
		<guid isPermaLink="false">http://quantologic.wordpress.com/?p=347#comment-790</guid>
		<description>hey.. can u pls xplain da flaw in dat differentiation method of proving 1=2..</description>
		<content:encoded><![CDATA[<p>hey.. can u pls xplain da flaw in dat differentiation method of proving 1=2..</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Concept 1 Perfect Squares by Rahul</title>
		<link>http://quantologic.wordpress.com/2008/08/25/concept-i-perfect-squares/#comment-789</link>
		<dc:creator>Rahul</dc:creator>
		<pubDate>Sun, 20 Sep 2009 04:57:18 +0000</pubDate>
		<guid isPermaLink="false">http://quantologic.wordpress.com/?p=5#comment-789</guid>
		<description>I came accross tnis link.... abt CAT 2009 WORKSHOPS 
http://www.mbaking.mbageeks.com/
Hope this is useful to every1 here preparin for CAT !!</description>
		<content:encoded><![CDATA[<p>I came accross tnis link&#8230;. abt CAT 2009 WORKSHOPS<br />
<a href="http://www.mbaking.mbageeks.com/" rel="nofollow">http://www.mbaking.mbageeks.com/</a><br />
Hope this is useful to every1 here preparin for CAT !!</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Concept 1 Perfect Squares by Rahul</title>
		<link>http://quantologic.wordpress.com/2008/08/25/concept-i-perfect-squares/#comment-788</link>
		<dc:creator>Rahul</dc:creator>
		<pubDate>Sun, 20 Sep 2009 04:56:05 +0000</pubDate>
		<guid isPermaLink="false">http://quantologic.wordpress.com/?p=5#comment-788</guid>
		<description>Hey grttt work thnks a lott</description>
		<content:encoded><![CDATA[<p>Hey grttt work thnks a lott</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Problem of the Day 3.07.09 by ananymous</title>
		<link>http://quantologic.wordpress.com/2009/07/02/problem-of-the-day-3-07-09/#comment-787</link>
		<dc:creator>ananymous</dc:creator>
		<pubDate>Sat, 12 Sep 2009 17:24:17 +0000</pubDate>
		<guid isPermaLink="false">http://quantologic.wordpress.com/?p=392#comment-787</guid>
		<description>AD = AB cos A
AE = AC cos a

ar(AED)/ar(ABC)  
= [(1/2) AE X AD cos A ]/[(1/2) AB X AC cos A] 
= (cos A)^2</description>
		<content:encoded><![CDATA[<p>AD = AB cos A<br />
AE = AC cos a</p>
<p>ar(AED)/ar(ABC)<br />
= [(1/2) AE X AD cos A ]/[(1/2) AB X AC cos A]<br />
= (cos A)^2</p>
]]></content:encoded>
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	<item>
		<title>Comment on Problem of the Day 3.07.09 by ananymous</title>
		<link>http://quantologic.wordpress.com/2009/07/02/problem-of-the-day-3-07-09/#comment-786</link>
		<dc:creator>ananymous</dc:creator>
		<pubDate>Sat, 12 Sep 2009 17:22:54 +0000</pubDate>
		<guid isPermaLink="false">http://quantologic.wordpress.com/?p=392#comment-786</guid>
		<description>AD = AB cos A
AE = AC cos a

ar(AED) = (1/2) AE X AD cos A   (cos A)^2
-------   ------------------- = 
ar(ABC)   (1/2) AB X AC cos A</description>
		<content:encoded><![CDATA[<p>AD = AB cos A<br />
AE = AC cos a</p>
<p>ar(AED) = (1/2) AE X AD cos A   (cos A)^2<br />
&#8212;&#8212;-   &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;- =<br />
ar(ABC)   (1/2) AB X AC cos A</p>
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	<item>
		<title>Comment on Problem of the day 25.07.09 by ahum.</title>
		<link>http://quantologic.wordpress.com/2009/07/25/problem-of-the-day-25-07-09/#comment-785</link>
		<dc:creator>ahum.</dc:creator>
		<pubDate>Fri, 11 Sep 2009 16:31:40 +0000</pubDate>
		<guid isPermaLink="false">http://quantologic.wordpress.com/2009/07/25/problem-of-the-day-25-07-09/#comment-785</guid>
		<description>how about the case in which the same box is chosen in every alternate turn to end up with the same no. of matches (duh...)
ABABABABABAB... 366 times ... so the prob wud be (1/2)^366</description>
		<content:encoded><![CDATA[<p>how about the case in which the same box is chosen in every alternate turn to end up with the same no. of matches (duh&#8230;)<br />
ABABABABABAB&#8230; 366 times &#8230; so the prob wud be (1/2)^366</p>
]]></content:encoded>
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