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Archive for the ‘Geometry’ Category

Bonus Question 26.07.09

with 11 comments

The perimeter of a right triangle is 60. The height to the hypotenuse is 12 what is the area?
(A) 75 (B) 144 (C) 150 (D) 300 (E) none of these

Written by Rahul

July 26, 2009 at 11:20 am

Problem of the day 17.07.09

with 9 comments

Find the area of right angle triangle whose inradius is 4 and circumradius
is 10?
a) 28                   b) 56                    c) 96                     d) 192                   e) none of these

Written by Rahul

July 16, 2009 at 2:35 pm

Problem of The day 13.07.09

with 6 comments

On a circle 26 equidistant points are marked. these points are joined to form a triangles. Of the triangles formed, how many of them will have their circumcenter on one of their sides.?

A) 318 B) 312 C) 288 d) 624 e) None of these

Problem of the Day 3.07.09

with 9 comments

In a triangle ABC, perpendiculars BD and CE are drawn to the sides AC and AB. Points  D and E are joined, then the ratio of the area of ADE to the area of ABC is:

1) Cos²A 2) Sin²A 3) Cot²A 4) Tan²A  5) None of these

Written by Rahul

July 2, 2009 at 6:00 pm

Problem of The Day 2.07.09

with 10 comments

Two triangles are considered distinct if they cannot be superimposed on each other by rotation. How many distinct triangles, with integer sides,  exist, such that there perimeter is 30?

A) 19    B) 57    C) 114    d) 38    E) 36

Written by Rahul

July 2, 2009 at 6:35 am

Posted in Geometry, Problem of the week

Tagged with , ,

Problem Of The Week 49

with 9 comments

Find the maximum area that can be bound by four line segments of length 1, 2, 3 and 4. (you are not allowed to break a segment, you may join two :) )

1) 6√2

2) 2√6

3) 4√6

4) 3√2

5) None of these

Written by Rahul

October 9, 2008 at 6:15 am

Problem Of The Week 45

with 10 comments

Find the largest value for for pairs of real numbers which satisfy

Written by Rahul

October 5, 2008 at 10:53 am

Problem Of The Week 32

with 4 comments

Four Equilateral triangles are formed taking one of their sides as the sides of the square, the third vertices of equilateral triangles being inside the square. The ratio of the area of fig formed by the third vertices of the triangles to that of the square is nearly

Written by Rahul

September 27, 2008 at 11:06 pm

Problem Of The Week 27

with 2 comments

A golden rectangle is a rectangle in which the ratio of the width to length is the same as that of the length to the sum of the length and width. Which of the following is also true about a golden rectangle?
I. The ratio of the length to width is the same as the ratio of the width to the difference of the length and width.
II. The product of the length and width is equal to the product of the sum of the two sides and the difference of the two sides.
III. The length has to be greater than two times the width.

(1) Only I and II (2) Only II and III
(3) Only I and III (4) All the three statements

(5) None of these

Written by Rahul

September 25, 2008 at 5:26 am

Problem Of The Week 19

with 4 comments

New Problem: A fresh one, I created it this morning, trying to find the most adequate data!

In a triangle ABC, altitude AD=6 is drawn to cut BC at D. From D, altitude DE=3 is drawn to cut AC at E. If it is know that AB =12. Find the ratio of the area of ABC to area of DEC?

A) 4:1 B) 16:1 C) 25:1 D) 5:1 E) Cannot be determined

Written by Rahul

September 20, 2008 at 3:16 am