Problem of the Day 30.07.09
Find the sum of the digits of the least natural number N, such that the sum of the cubes of the four smallest distinct divisors of N is 2N?
1) 9 2) 8 3) 7 4) 6 5) 10
N=126; (1)
anonymous
August 1, 2009 at 5:16 pm
can u plz explain the method ?
nikhil jangi
August 3, 2009 at 11:51 am
I used hit and trial, guessed it would be the quickest approach to solve it.
Start with 1,2,3,4 then 1,2,3,6 (which fetches the answer)
anonymous
August 4, 2009 at 7:10 pm
hit N trial method N u will get 126.
ANKIT PANGHAL
August 10, 2009 at 10:09 am
If the number is even then 1 and 2 are gonna be its two divisors.The remaining 2 divisors could be p and 2p for sure then(taking p as a prime number).We can check p for 3,5,7 and 3 will give the answer by meeting all the conditions.
A nkur Dudeja
August 18, 2009 at 1:56 pm
Rahul pls put the approach to this question and answer to it..
Prateek
August 20, 2009 at 7:50 pm