Problem of the day 17.07.09
Find the area of right angle triangle whose inradius is 4 and circumradius
is 10?
a) 28 b) 56 c) 96 d) 192 e) none of these
For All Your Quant Queries
96
Nikhil
July 16, 2009 at 3:31 pm
Nice, yet again!
Rahul
July 16, 2009 at 3:50 pm
Is the length of the altitutude (drawn to the hypotenuse) = 1/2(length of hypot.?)
if so..the hyp=28..is that correct??
Sam
July 17, 2009 at 9:23 am
no boss
its 20 hyp
kuldeep
July 20, 2009 at 1:02 pm
ans is 96
rahul sir i met you once in CL,you gave lecture on better preparation in gagan sir’s class.
you are doing great job..i owe much to your lessons/concepts
thank you
shivam
shivam
July 24, 2009 at 8:22 am
Shivam
I am sure you are mistaking me for someone else.
I am not aware of any gagan sir and have never been to a Cl class
Rahul
July 24, 2009 at 8:59 pm
how to solve this problem
rahul
July 25, 2009 at 2:43 pm
the smallest right triangle is 345
with inradius 1 and circumradius 2.5
what we need is a triangle which has four times the given values
hence the area will be 16 times that of the given triangle
hnce 16×6=96
Rahul
July 25, 2009 at 2:46 pm
thank’s Rahul
rahul
July 26, 2009 at 11:44 am