i would like to clearify that its the fermat rule that
x^n + y^n = z^n…n>=3 has no sloution…else we can solve it by jst hit n trial and reach the solution
Fermat’s last theorem states that there is no NON trivial solution for the equation written above for n > 2. (0,0,0) is always a solution to such equation for all n>0.
intuitively, the fourth powers are 1,16,81,256,… etc.. for bigger numbers the gap between these fourth powers is too huge to be compensated by a smaller fourth power. so this equation can only be fulfilled among the smaller fourth powers. however as is evident from these numbers, no such combination is possible. so 0
choice A) 0 ??
Sam
July 17, 2009 at 9:34 am
rahul,can u tell the solution of this question
Prateek
July 17, 2009 at 9:48 am
it’s the fermat’s last theorem.And no one till date has been able to prove this.
x^n + y^n = z^n for n>2 (does not hold).
yodha
July 17, 2009 at 3:13 pm
answer : 0
yodha’ sol sounds correct .
but in case a person isnot aware of fermat’s last theorem then what ??
nikhil
July 18, 2009 at 6:52 am
the solution is right..
we do not have a perfect solution for this question.
but intutively we can solve this
Rahul
July 23, 2009 at 6:46 am
clearly 0 is a solution
ANKIT PANGHAL
August 10, 2009 at 10:04 am
i would like to clearify that its the fermat rule that
x^n + y^n = z^n…n>=3 has no sloution…else we can solve it by jst hit n trial and reach the solution
ANKIT PANGHAL
August 13, 2009 at 4:27 am
Fermat’s last theorem states that there is no NON trivial solution for the equation written above for n > 2. (0,0,0) is always a solution to such equation for all n>0.
Kshitiz
October 11, 2009 at 11:36 am
In Fermat’s last theorem n is integer. And it has been proven in 1993 by Andrew Wiles and Richard Taylor.
Kshitiz
October 11, 2009 at 11:37 am
intuitively, the fourth powers are 1,16,81,256,… etc.. for bigger numbers the gap between these fourth powers is too huge to be compensated by a smaller fourth power. so this equation can only be fulfilled among the smaller fourth powers. however as is evident from these numbers, no such combination is possible. so 0
Pranshu
November 10, 2009 at 2:46 pm