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Archive for June 25th, 2009

Problem of the day 25.06.09

with 6 comments

The real numbers, x, y, z, w satisfy

2x+y+z+w=1

x+3y+z+w=2

x+y+4z+w=3

x+y+z+5w=25

Find w.

Options

1. 2

2. 7/2

3. 11/2

4. 5

5. None of these

Written by Rahul

June 25, 2009 at 4:57 am

Posted in Algebra, Problems